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(a)   BA, AD, DC (b)  DC, CB, BA (c)   AB, BC, CD (d)  CD, DA, AB Explanation-(d)   Process CD is...
(a)  C and D respectively (b)  D and C respectively (c)   A and B respectively (d)   B and A respectively...
(a)      He and O2 (b) O2 and He (c)   He and Ar (d) O2  and N2 Answer-b (141)
PA=3×104 Pa and  PB=8×104 Pa, VA=2×10-3 m3 and VD=5×10-3 m3 . In process AB, 600 J of heat is added to...
β=-(dV/dP)/V  with P for an ideal gas at constant temperature Answer-a (108)
Q1,Q2 and Q3 denote the heat absorbed by the gas along the three paths, then (a)  Q1 < Q2 <...
(a)  840 K                                 (b)  280 K (c)   560 K                                 (d)  380 K Answer-d (84)
(a)      20 J (b)  – 20 J (c)   400 J (d)  – 374 J Ans. b (64)
ΔU1 and ΔU2 are the changes in internal energies in the processes I and II respectively, then (a) ΔUII  >...
(Cp/Cv=γ) is at pressure P1 and temperature T1 in left part and gas at pressure P2 and temperature T2 in right...
(a)  4 R                                      (b)  2.5 R (c)   3 R                                      (d) 4R/3 Answer-c (11)
PV2= constant. During this process, the gas is (a)  Heated (b)  Cooled (c)   Neither heated nor cooled (d)  First heated...
(a)  – 4.5 cal/K                                 (b)  + 4.5 cal/K (c)   +5.4 cal/K                   ...
(a)  80°C, 37°C                                (b)  95°C, 28°C (c)   90°C, 37°C                       ...
  (a)  2 moles of helium occupying  1m3 at 300 K (b)  56 kg of nitrogen at 107N/m2 and 300...
(a)  40 %                                  (b)  30 % (c)   60 %                                  (d)  20 % Answer-a (9)
T1=800K and rejects to sink at T2K . The second engine B receives heat rejected by the first engine and...
(a) PV3/2  = constant             (b) PV5/2 = constant (c)  PV7/3 = constant             (d) PV4/3 = constant Answer-a (7)
(a)  5%                                     (b)  6% (c)   7%                                     (d)  8% Answer-c (4)
(a)   (2/5)R                               (b)  (5/2)R (c)  (10/3)R ...
temperature is T0, atmospheric pressure is also P0. Now the temperature of the gas is increased to 2T0, the tension...
volume V1 to V2  for a gas which obeys Vander Waal’s equation (V – βn)[ P + (αn2/v)= nRT (a) ...
(a)  4 RT                                    (b)  15 RT (c)   9 RT                                    (d)  11 RT Ans. d (16)
(a) PV3/2 = constant             (b) PV5/2 = constant (c) PV7/3  = constant             (d) PV4/3= constant Answer-a (9)
(a)  5%                                     (b)  6% (c)   7%                                     (d)  8% Answer-c (6)
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