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33. An aluminum rod (Young’s modulus

33. An aluminum rod (Young’s modulus=7×109 N/m2) has a breaking strain of 0.2%. The minimum cross-sectional area of the rod in order to support a load of  104  Newton’s is

(a)   1×10-2 m2                                       (b)  1.4×10-3 m2

(c)  3.5×10-3 m2                                      (d)   7.1×10-4 m2

Answer-d

(56)

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