33. An aluminum rod (Young’s modulus
33. An aluminum rod (Young’s modulus=7×109 N/m2) has a breaking strain of 0.2%. The minimum cross-sectional area of the rod in order to support a load of 104 Newton’s is
(a) 1×10-2 m2 (b) 1.4×10-3 m2
(c) 3.5×10-3 m2 (d) 7.1×10-4 m2
Answer-d
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(a) – 5 J (b) – 10 J (c) – 15 J (d) – 20 J Answer-a