Ans. d (8)
a. Nylon -66 b. Terylene c. Teflon d. Bakelite Ans. a (16)
a. Nil b. Weak c. Strong d. Very strong Ans. b (6)
a. Neoprene b. Teflon c. Thiokol d. PVC Ans. b (5)
a. Styrene b. Tetrafluoro ethylene c. Vinyl chloride d. Acrylonitrile Ans. d (15)
a. Melamine and tetrafluoroethane b. Malonic acid and hexamethyleneamine c. Melamine and vinyl acetate d. Melamine and formaldehyde Ans. d (8)
a. Protein b. Nylon c. Peptide d. All of these Ans. d (6)
a. They have high molecular weights and high melting points b. They have a high degree of cross- linking by strong C- C bond c. They have linear molecules consisting of very long chains d. They have linear molecules interlinked …
a. Increases b. Decreases c. Remains unchanged d. Uncertain Ans. a (15)
(a) mgR n/n-1 (b) nmgR (c) mgR n2/n2+1 (d) mgR n/n+1 Answer: …
(a) 3.80×108 metres (b) 3.37 ×106 metres (c) 7.60×104 metres (d) 1.90×102 metres Answer: a (43)
a. Polythene b. Perspex c. Teflon d. Bakelite Ans. c (6)
a. Nylon – 6 b. Teflon c. Terylene d. Bakelite Ans. a (6)
a. Ethylene b. 1- chloroethene c. Propene d. 1 – chloroethene Ans. d (6)
a. Benzene b. Phenyl amine c. Benzaldehyde d. Phenol Ans. d (6)
a. Monofluoroethene b. Difluoroethene c. Trifluoroethene d. Tetrafluoroethene Ans. d (5)
The compound that does not undergo polymerization under radical initiation, is a. (i) b. (ii) c. (iii) d. (iv) Ans. d (8)
24.To double the length of a iron wire having area of cross-section 0.5 cm2, the required force will be (Y=1012 dyne/cm2) (a) 1.0×10-7 N (b) …
a. Hexamethylene diamine and ehhylene glycol b. Adipic acid and ethylene glycol c. Adipic acid and hexamethylene diamine d. Dimethyl terephthalate and ethylene glycol Ans. c (11)
a. Bakelite b. Polystyrene c. Nylon d. PVC Ans. a (11)
a. Propene b. Butadiene c. Adipi acid d. Amino acid Ans. d (7)
a. (i) b. (ii) c.(iii) d. (iv) Ans. a (6)
a. Bakelite b. Nylon 6, 6 c. Terylene d. Nylon 6 Ans. d (9)
(a) 2/3π2f2ml2 (b) 4/3 f2ml2 (c) 4π2f2ml2 (d) Zero Ans. a (19)
a. RSiCl 3 b. R 2 SiCl 2 c. R 3 SiCl d. R4 Si Ans. a (4)
a. CH 3 SiCl 3 and Si (CH 3 ) 4 b. (CH3 ) 2 SiCl 2 and (CH 3) 3 SiCl c. (CH3 ) 2 SiCl 2 and CH 3 SiCl 3 d. SiCl 4 and (CH 3) 3 SiCl Ans. b (4)
a. LialH 4 b. HNO 3 c. AlCl 3 d. BuLi Ans. c (12)
(a) 2π2 In2 (b) 4π2 In2 (c) 6π2 In2 (d) 8π2 In2 Ans. c (31)
a. Wolf rearrangment b. Amadori rearrangement c. Curtius rearrangement d. Beckmann rearrangement Ans. d (44)