24.To double the length of a iron wire having area of cross-section 0.5 cm2, the required force will be (Y=1012 dyne/cm2)
(a) 1.0×10-7 N (b) 1.0×107 N
(c) 0.5×10-7 N (d) 0.5×1012 N dyne
Explanation-d
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