The escape velocity for a body projected vertically upwards from the surface of earth is 11 km/s. If the body is projected at an angle of 45o with the vertical, the escape velocity will be
(a) ( 11/√2 )km/s (b) 11√2km/s
(c) 22 km/s (d) 11 km/s
Answer: d
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(a) – 5 J (b) – 10 J (c) – 15 J (d) – 20 J Answer-a