Brand new Course Package released! Get 99% off your first purchase with code “99”. Find out more!

0

Shopping cart

Close

No products in the cart.

The displacement x of a particle moving in one dimension under the action of a constant force is related to the time t by the equation t=√x+3 , where x is in meters and t is in seconds. The work done by the force in the first 6 seconds is

(a) 9 J (b) 6 J

(c) 0 J (d) 3 J

Answer: C

(6)

5/5 - (2 votes)

PrevPreviousA force F = -K(yi+xj) (where K is a positive constant) acts on a particle moving in the xy-plane. Starting from the origin, the particle is taken along the positive x-axis to the point (a, 0) and then parallel to the y-axis to the point (a, a). The total work done by the force F on the particles is

NextA particle of mass m is moving in a horizontal circle of radius r under a centripetal force equal to -K/r2 , where K is a constant. The total energy of the particle isNext

You May Also Like

Sign up to receive latest updates

Get in touch

Need some help?

Popular subjects

Need some help?

© 2025 Flame Institute.All rights reserved.

error: Content is protected !!