The depth d at which the value of acceleration due to gravity becomes 1/n times the value at the surface, is [R = radius of the earth]
(a) R/N (b) R ( n-1/n )
(c) R/n2 (d) R (n/n+1 )
Answer: b
(8)
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(a) – 5 J (b) – 10 J (c) – 15 J (d) – 20 J Answer-a (126)