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In the following four periods

(i)   Time of revolution of a satellite just above the earth’s surface(Tst)

(ii)  Period of oscillation of mass inside the tunnel bored along the diameter of the earth(Tma)

(iii) Period of simple pendulum having a length equal to the earth’s radius in a uniform field of 9.8 N/kg(Tsp)

(iv) Period of an infinite length simple pendulum in the earth’s real gravitational field(Tis)

(a)  Tst>Tma                         (b) Tma >Tst

(c)   Tsp< Tis                          (d)   Tst  = Tma   = Tsp =  Tis

Answer:c

(7)

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