In the following four periods
(i) Time of revolution of a satellite just above the earth’s surface(Tst)
(ii) Period of oscillation of mass inside the tunnel bored along the diameter of the earth(Tma)
(iii) Period of simple pendulum having a length equal to the earth’s radius in a uniform field of 9.8 N/kg(Tsp)
(iv) Period of an infinite length simple pendulum in the earth’s real gravitational field(Tis)
(a) Tst>Tma (b) Tma >Tst
(c) Tsp< Tis (d) Tst = Tma = Tsp = Tis
Answer:c
(7)