If the gravitational force between two objects were proportional to 1/R (and not as 1/R2) where R is separation between them, then a particle in circular orbit under such a force would have its orbital speed v proportional to
(a) 1/ R2 (b) R°
(c) R1 (d) 1/R
Answer: b
(12)
5/5 - (2 votes)