Flame Institute SCF 18 Near Chawla Lights Phase 7 Mohali Chandigarh 9888949978

0

Shopping cart

Close

No products in the cart.

Flame SCF 18 Near Chawla Lights Ph-7 Mohali 9888949978

Escape velocity on a planet is ve . If radius of the planet remains same and mass becomes 4 times, the escape velocity becomes

(a) 4 v_e (b) 2 v_e

(c) v_e (d) 1/2 v_e

Answer: b

5/5 - (2 votes)

PrevPreviousThe escape velocity of an object from the earth depends upon the mass of the earth (M), its mean density (p), its radius (R) and the gravitational constant (G). Thus the formula for escape velocity is

Next142. A solid ball of mass m and radius r rolls without slipping along the track shown in the fig. The radius of the circular part of the track is R. The ball starts rolling down the track from rest from a height of 8R from the ground level. When the ball reaches the point P then its velocity will beNext

You May Also Like

Sign up to receive latest updates

Get in touch

Need some help?

Create Account

Popular subjects

Need some help?

© 2026 Flame Institute.All rights reserved.

Call Now Button