16.The length of a rod is 20 cm and area of cross-section 2 cm2 . The Young’s modulus of the material of wire is 1.4×1011 N/m2 . If the rod is compressed by 5 kg-wt along its length, then increase …
(a) 3 : 2 (b) 2 : 3 (c) 3 : 4 (d) 4 : 3 Answer-a (23)
(a) √(2E)/Y (b) √(2E) (c) EY …
(a) 0.01 J (b) 0.02 J (c) 0.04 J (d) 1.00 J Answer-a (37)
10. A brass rod of cross-sectional area 1cm2 and length 0.2 m is compressed lengthwise by a weight of 5 kg. If Young’s modulus of elasticity of brass is 1×1011 N/m2 and g=10 m/sec2 , then increase in the energy of …
(a) Converts into kinetic energy (b) Converts into heat energy (c) Remains as potential energy (d) None of the above Answer-b (9)
(a) Remains constant (b) Decreases (c) Increases (d) None of the above Answer-c (13)
(a) It will break (b) Its temperature will reduce (c) There will be no change in its temperature (d) Its temperature increases Answer-d (12)
(a) Kl/2 (b) Kl (c) Kl2 /2 …
(a) Zero (b) 0.05 joule (c) 100 joule (d) 500 joule Answer-b (16)
(a) 1 : 2 (b) 1 : 4 (c) 2 : 1 (d) 1 : 1 Answer-a (19)
(a) Mgl (b) Zero (c) Mgl/2 …
(a) Stress × Strain (b) (1/2)(Stress× Strain) (c) 2× Stress × Strain (d) Stress/Strain Answer-b (8)
(a) V/25 (b) 5V (c) V/5 (d) 25V Answer-d (4)
A solid sphere rolls down an inclined plane and its velocity at the bottom is v1. Then same sphere slides down the plane (without friction) and let its velocity at the bottom be v2. Which of the following relation is …
(a) 1.4 m/sec (b) 0.14 m/sec (c) 14 m/sec (d) 0.7 m/sec Ans .a (26)
(a) 15 : 14 (b) √15:√14 (c) 14 : 15 (d) √14:√15 Ans. d (6)
A thin uniform circular ring is rolling down an inclined plane of inclination 30° without slipping. Its linear acceleration along the inclined plane will be (a) g/2 (b) g/3 (c) g/4 (d) 2g/3 Ans. c (8)
(a) Ring, disc, sphere (b) Sphere, disc, ring (c) Disc, ring, sphere (d) Sphere, ring, disc Ans. b (16)
(a) 5/7 g sin θ (b) 3/5 g sin θ (c) 2/7 g sin θ (d) 2/5 g sin θ Ans. a (6)
(a) √(3/4) gh (b) √(4/3)gh (c) √4gh (d) √2gh Ans. b (19)
A body of moment of inertia of 3 kg-m2 rotating with an angular velocity of 2 rad/sec has the same kinetic energy as a mass of 12 kg moving with a velocity of (a) 8 m/s (b) 0.5 m/s (c) …
(a) 350 N-m (b) 440 N-m (c) 531 N-m (d) 628 N-m Ans. c (14)
(a) Shape (b) Size (c) None (d) Shape and size Answer-d (60)
(a) Volume stress (b) Shearing strain (c) Longitudinal strain (d) Metallic strain Answer-b (7)
(a) 10 J (b) 100 J (c) 500 J (d) 250 J Ans. d (25)
(a) 0.12 J–s (b) 12 J–s (c) 1.2 J-s (d) 1.12 J-s Ans. a (10)
(a) 0.3 rad/s (b) 5.3 rad/s (c) 10.3 rad/s (d) 89.3 rad/s Ans. c (9)
(a) 2.4 (b) 1.2 (c) 0.4 (d) 0.2 Answer-d (17)
(a) Non zero constant (b) Infinite (c) Zero (d) Can not be predicted Answer-c (18)
(a) 0.3 rad/s (b) 5.3 rad/s (c) 10.3 rad/s (d) 89.3 rad/s Ans. c (5)
(a) Zero (b) Infinity (c) 2×1010 N/m2 (d) 3×1010 N/m2 Answer-b (10)
Moment of inertia of uniform rod of mass M and length L about an axis through its centre and perpendicular to its length is given by ML2/12 . Now consider one such rod pivoted at its centre, free to rotate …
(a) r1 2 /r2 2 (b) r2 2 /r1 2 (c) r2 4 /r1 4 …
The Young’s modulus of the material of a wire is 6×1012 N/m2 and there is no transverse strain in it, then its modulus of rigidity will be (a) 3×1012 N/m2 (b) 2×1012 N/m2 (c) 1012 N/m2 …
A smooth uniform rod of length L and mass M has two identical beads of negligible size, each of mass m, which can slide freely along the rod. Initially the two beads are at the centre of the rod and …