Al2 (SO4)3 {d= 1.253 gm/mL } contain 22% salt by weight. The molarity, normality and molality of the solution is a. 0.805 M, 4. 83 N, O.825 m b. 0.805 M, 48.3 N, O.80s m c. 4.83 M, 4. 83 …
a. Molarity b. Molality c. Formality d. Normality Ans. b Explanation : Calculation of molality does not have a volume component. (16)
mol-1 is dissolved in 100 mL of water to obtain a solution whose density is 1.25 g mL-1 The molarity and molality of the solution are respectively a. 0.75 and 1 b. 0.8 and 1 c. 1 and 0.8 d. 1 …
a. 1m b. 0.5 m c. 0.2 m d. 2m Ans. c (6)
a. ppm by weight of MgSO4 b. g/L of CaCO3 and MgCO3 c. ppm by weight of CaCO 3 irrespective of whether it is actually present d. ppm of CaCO3 actully present in water Ans. c (8)
a. 14 b. 3.2 c. 4 d. 2 Ans. b (8)
a. 0.027 b. 0.036 c. 0.018 d. 0.009 Ans. c (9)
a. 250 b. 200 c. 400 d. 1000 Ans. c (6)
a. Molality b. Weight fraciton of solute c. Fraction of solute present in water d. Mole fraction Ans. c Explanation : Since fraction of solute present in water depends on the volume of water, it will change with the increase …
a. o.177 b. 1.770 c. 0.0354 d. 0.0177 Ans. d (5)
H2 O. The mole fraciton of urea is a. 10/10.1 b. 10.1/10 c.10.1/0.1 d. 0.1/10.1 Ans. d (9)
a. 1000 g of the solvent b. One litre of the solvent c. One litre of the solution d. 22.4 litres of the solution Ans. a Explanation : The number of moles of solute dissolved in 1000 g of the …
CaCO3 contains 10 gms of carbonate. Concentration of the solution is a. 10 ppm b. 100 ppm c. 1000 ppm d. 10000 ppm Ans. d (10)
H2 O2 is a. 77/68 b. 68/77 c. 20/80 d. 80/20 Ans. b (40)
a. Gram per million b. Milligram percent c. Microgram percent d. Nano gram percent e. Part per million Ans. e (11)
a. 0. 176 b. 3. 52 c. 1. 78 d. 0.88 e. 17. 8 Ans. c (8)
H2 SO4 and 30 mL of N/3 HNO3 are mixed together and volume made to one litre. The normality of the resulting solution is a. N/5 b. N/10 c. N/20 d. N/40 e. N/ 25 Ans. d (6)
0.2 N – NaOH solution. a. 0.45 g b. 0.90 g c. 1.08 g d. 1. 26 g Ans. d (38)
a. 4.0N H2 SO4 b. 0.5 N H2 SO4 c. 1 N H2 SO4 d. 2N H2 SO4 Ans. a (13)
20° C and NaCl concentration is 3.5% the normality of the sea water is a. 0.65 N b. 0.68 N c. 0.66 N d. 0.61 N Answer : d (4)
a. o.97 N b. 0.142 N c. 0.194 N d. 0.244 N Ans. c (12)
N H2 SO4 and the mixture is made one litre. Normality of the mixture will be a. 0.56 N b. 0.50 N c. 0.40 N d. 0.35 N Ans. b (6)
a. 13. 25 g b. 26. 5 g c. 53 g d. 6.125 g Ans. a (10)
H2 SO4 (18 molar) is diluted to 1 litre. The approximate strength of dilute acid could be a. 0.18 N b. 0.09 N c. 0.36 N d. 1800 N Ans. c (12)
a. HCl b. perchloric acid c. HNO3 d. phosphoric acid Ans. d (10)
a. 40 mL b. 20mL c. 10mL d. 60 mL Ans. a (8)
a. 2N b.4N c. N/2 d. N/4 Ans. b Explanation : N = M x basicity ; N = 2 x 2 = 4 (14)
a. 0. 5 L of A + 1.5 L of B b. 1.5 L of A + 0.5 L of B c. 1.0 L of A + 1.0 L of B d. 0. 75 L of A + 1.25 L …
1.2046 x 106 hydrochloric acid molecules in one dm3 of the solution . The strength of the solution is a. 6 N b. 2N c. 4N d. 8 N Ans. b (13)
10N HNO3 to get 0.1 N HNO3 a. 1000 mL b. 990 mL c. 1010 mL d. 10 mL Ans. b Explanation : N1 V1 = N2 V2 10 x 10 = 0.1 (10+V) V = 10 x 10 / …
100 cm3 of 0.5 N H2 SO4 to get decinormal concentration is a. 400 cm3 b. 500cm3 c. 450 cm3 d. 100 cm3 Ans.a (7)
a. 1g b. 2g c. 10 g d. 20 g Ans. a (3)
a. 100 L b. 10 L c. 1L d. 1000 L Ans. b (8)
a. 8 g of KOH / L b. N phosphoric acid c. 6 g of NaOH/ 100 mL d. 0.5 M H2 SO4 Ans. c (13)
a. 0.1 b. 40 c. 1.0 d. 0.4 Ans. c (11)
K2 Cr2 O7 required to prepare 100 mL of its 0.05 N solution is a. 2. 9424 g b. 0.4904 g c. 1.4712 g d. 0.2452 g Ans. d (8)
a. 0.75 litre of 10 N HCl and 0.25 litre of 4 N HCl b. 0.25 litre of 4 N HCl and 0.75 litre of 10 N HCl c. 0.67 litre of 4 N HCl and 0.33 litre of 10 …