(a) 350×40.4 K (b) 300×40.4 K (c) 150×40.4 K (d) None of these Answer-b (2)
(a) 1 : 16 (b) 1 : 8 (c) 1 : 4 (d) 8 : 1 Answer-d (3)
(a) Lesss than P (b) More than P (c) P (d) Either (a) or (c) Answer-b (5)
(a) ΔU=-W in an adiabatic process (b) ΔU=W in an isothermal process (c) ΔU=-W in an isothermal process (d) ΔU=W in an adiabatic process Answer-a (2)
(a) Adiabatic expansion (b) Adiabatic compression (c) Isothermal expansion (d) Isothermal compression Answer-b (5)
105 N/m2 . On suddenly pressing the piston the volume is reduced to half the initial volume. The final pressure of the gas is (a) 20.7 ×105 (b) 21.3 ×105 …
(a) 273 K (b) 573 K (c) 373 K (d) 473 K Answer-a (6)
(a) (T+2.4)K (b) (T-2.4)K (c) (T+4)K (d) (T-4)K Answer-d (8)
(a) Its pressure increases (b) Its temperature falls (c) Its density increases (d) Its thermal energy increases Answer-b (5)
Cp/Cv for the gas is (a) 3/2 (b) 4/3 (c) 2 (d) 5/3 Answer-a (10)
(P1,V1,T1) to (P2,V2,T2) . Which of the following relation is correct (a) T1V1γ-1=T2V2γ-1 (b) P1V1γ-1=P2V2γ-1 (c) T1P1γ=T2P2γ (d) T1V1γ=T2V2γ Answer-a (9)
(a) P‘=P (b) P‘=2P (c) P‘=P ×215/2 (d) P‘=7P Answer-c (8)
(a) 27.5°C (b) 75°K (c) 150K (d) 150°C Answer-c (3)
(a) 627°C (b) 527°C (c) 427°C (d) 327°C Answer-d (12)
(a) Adiabatic process (b) Isothermal process (c) Isobaric process (d) Isochoric process Answer-a (4)
(a) 420K (b) 327°C (c) 300K (d) -142°C …
(a) -2767.23 J (b) 2767.23 J (c) 2500J (d) -2500J Answer-b (3)
(a) Isochoric (b) Isobaric (c) Isothermal (d) Adiabatic Answer-(d) In adiabatic process, no transfer of heat takes place between system and surrounding. (4)
(a) Zero (b) Infinite (c) Finite but non-zero (d) Undefined Answer-a (6)
(a) 10°C (b) 887°C (c) 668K (d) 144°C …
(a) dQ=0 (b) dU=-dW (c) Q = constant (d) Entropy is not constant Answer-d (9)
(a) 1280 J (b) 1610 J (c) 1815 J (d) 2025 J Answer-c (6)
T to T1 is (a) R(T-T1) (b) [R/(γ-1)](T-T1) (c) RT (d) R(γ-1)(T-T1) Answer-b (8)
change is ( γ=Cp/Cv ) (a) PTγ constant (b) PT-1+γ constant (c) Pγ-1 Tγ constant (d)P1-γ Tγ constant Answer-d (62)
(a) Isothermal curve slope = adiabatic curve slope (b) Isothermal curve slope =γ× adiabatic curve slope (c) Adiabatic curve slope = γ× isothermal curve slope (d) Adiabatic curve slope =(1/2)× isothermal curve slope Answer-c (6)
(Pi,Vi,Ti) to its final state (Pf,Vf,Tf) . The decrease in the internal energy associated with this expansion is equal to (a) Cv(Ti-Tf) (b) CP(Ti-Tf) (c) (1/2)(Cp+Cv)(Ti-Tf) …
(a) Isothermal process (b) Isobaric process (c) Isochoric process (d) Adiabatic process Ans. d (10)
270 has a volume of 8 litres.It is suddenly compressed to a volume of 1 litre. The temperature of the gas will be [ϒ = 5/3] (a) 1080C …
are T1 and T2 respectively, then the change in internal energy of the gas is (a) (R/ϒ-1) (T2-T1) (b) (R/ϒ-1) (T1-T2) (c) R(T1-T2) …
(a) Zero (b) –100 J (c) 200 J (d) 100 J Ans. d (14)
(a) Isothermal change (b) Adiabatic change (c) Isobaric change (d) Isochoric change Answer-b (7)
(a) 227.36 K (b) 500.30 K (c) 454.76 K (d) -47°C Answer-a (5)
(γ=Cp/Cv) (a) PγV = constant (b)TγV = constant (c) TVγ-1 =constant (d) TVγ = constant Answer-c (6)
P0 , its new pressure will be (a) 8P0 (b) 16P0 (c) 6P0 (d) 2P0 Answer-b (2)
(a) P (b) 2P (c) P/2 (d) γP Answer-d (8)
(a) Starts becoming hotter (b) Remains at the same temperature (c) Starts becoming cooler (d) May become hotter or cooler depending upon the amount of water vapour present Answer-c (3)
(a) 2077.5 joules (b) 207.5 joules (c) 207.5 ergs (d) None of the above Answer-a (18)
(a) No energy is required for expansion (b) Energy is required and it comes from the wall of the container of the gas (c) Internal energy of the gas is used in doing work (d) Law of conservation of energy …
(a) The pressure decreases (b) The pressure increases (c) The pressure remains the same (d) The pressure may increase or decrease depending upon the nature of the gas Answer-a (5)