(a) 300 K (b) 400 K (c) 500 K (d) 700 K Answer-a (3)
(a) Q / 4 (b) Q / 3 (c) Q / 2 (d) 2Q / 3 Answer-b (2)
(a) Isothermal (b) Adiabatic (c) Isobaric (d) None of these Ans. a (13)
27°C has a movable piston which maintains at constant pressure in container of 1 atm. The gas is compressed until temperature becomes 127°C. The work done is (Cp for gas is 7.03 cal/mol–K) (a) 703 J …
(a) T2 =273K (b) T2 =0 K (c) T1 =273K (d) T1 =0 K Answer-b (5)
(a) 127°C (b) 227°C (c) 327°C (d) 673°C Answer-b (6)
6 × 104 J at high temperature. The amount of heat converted into work is …. (a) 4.8 × 104 J (b) 3.5 × 104 J (c) 1.6 × 104 J (d) 1.2 × 104 J Answer-d (6)
(a) Zero (b) Equal to heat given to the system (c) More than the heat given to system (d) Independent of heat given to the system Answer-b (12)
(a) In the whole cycle of the system, the loss of any type of heat energy should be zero (b) That the process should be too fast (c) That the process should be slow so that the working substance …
(a) Adiabatic process (b) Joule-Thomson expansion (c) Ideal isothermal process (d) None of the above Answer-b (13)
(a) Increases (b) Decreases (c) Remains constant (d) Becomes zero Explanation-(c) Internal energy is a state function. (10)
(a) Room is cooled (b) Room is heated (c) Room is either cooled or heated (d) Room is neither cooled nor heated Explanation-(b) In a refrigerator, the heat dissipated in the atmosphere is more than that taken from the cooling …
(a) 10 (b) 1 (c) 9 (d) 0 Answer-c (4)
(a) 1800 J/cycle (b) 1000 J/cycle (c) 2000 J/cycle (d) 1600 J/cycle Answer-d (3)
(a) ΔQ = ΔU (b) ΔW = ΔU (c) ΔQ = ΔW (d) None of these Ans. a (16)
(a) In an isobaric process, ΔP =0 (b) In an isochoric process, ΔW = 0 (c) In an isothermal process, ΔT = 0 (d) In an isothermal process, ΔQ = 0 Ans. d (30)
if T1 = 270C and T2 = 1270C , then P1/P2 will be equal to (a) 9 / 59 (b) 2 / 3 (c) 3 / 4 …
(a) Isobaric (b) Isothermal (c) Adiabatic (d) Isochoric Ans. d (7)
(a) Isothermal process (b) Adiabatic process (c) Isochoric process (d) None of these Ans. c (8)
(a) Conduction of heat from a hot reservoir to a cold reservoir (b) Conversion of heat into work isobarically (c) Conversion of heat into internal energy isochorically (d) Conversion of work into heat isochorically Ans. d (13)
(a) 28 joule (b) 27 joule (c) 25 joule (d) 24 joule Ans. d (4)
(a) -√γ ΔV/V (b) -ΔV/V (c) -γ ΔV/V (d) -γ2 ΔV/V Answer-c (7)
(a) –166 J (b) 166 J (c) –168 J (d) 168 J Answer-b (6)
V1 to V2 . The amount of work done by the gas is greatest when the expansion is (a) Isothermal (b) Isobaric (c) Adiabatic (d) Equal in all cases Ans. b (20)
(a) Adiabatic < Isothermal < Isobaric (b) Isobaric < Adiabatic < Isothermal (c) Adiabatic < Isobaric < Isothermal (d) None of these Ans. c (20)
(a) Temperature (b) Pressure (c) Heat (d) Temperature and pressure Explanation-(c) In adiabatic process, no heat transfers between system and surrounding. (7)
V1 is completely changed into a gas of volume V2 at a constant external pressure P and temperature T. If the latent heat of evaporation for the given mass is L, then the increase in the internal energy of the …
(a) 540 ml (b) 350 ml (c) 280 ml (d) 135 ml Answer-c (18)
Vo at 27°C. It is heated at constant pressure so that its volume becomes 2Vo. The final temperature is (a) 54°C (b) 32.6°C (c) 327°C …
2×10-3 m3 to 3.34 m3. The work done by the system is about (a) – 340 kJ (b) – 170 kJ (c) 170 kJ (d) 340 kJ Answer-d (4)
0.25m3 at constant pressure 103 N/m2 , the work done is (a) 2.5 ergs (b) 250 J (c) 250 W (d) 250 N Answer-b (6)
(R = 2 cal mol–1 oC–1) (a) 54 cal (b) 600 cal (c) 60 cal (d) 546 cal Answer-c (9)
(a) 2×104 joules (b) 2×100 joules (c) 2×105×100 joules (d) 2×10–5×100 joules Answer-a (8)
50 N/m2 from a volume of 10m3 to a volume of 4m3 . Energy of 100 J then added to the gas by heating. Its internal energy is (a) Increased by 400 J (b) Increased by 200 J (c) Increased …
(a) The work is done by the gas (b) Internal energy of the gas increases (c) Both (a) and (b) (d) None from (a) and (b) Answer-c (5)
V1 to V2. The work done by the gas is (a) P(V2-V1) (b) P(V1-V2) (c) P(V1γ-V2γ) (d) (PV1V2)/(V2-V1) Answer-a (6)
2.1×105N/m2. What will be its isothermal modulus of elasticity[(Cp/Cv)=1.4] (a) 1.8×105N/m2 (b) 1.5×105N/m2 (c) 1.4×105N/m2 (d) 1.2×105N/m2 Answer-b (14)
(a) Zero (b) 100J (c) – 50J (d) 50J Answer-d (8)