(a) Tc =(8a)/27Rb (b) Tc =(a)/2Rb (c) Tc =(8)/27Rb (d) Tc =(27a)/8Rb Answer-a (8)
(a) Four times the value at 200 K (b) Half the value at 200 K (c) Twice the value at 200 K (d) Same as at 200 K Answer-c (12)
(a) 20 K (b) 80 K (c) – 73 K (d) 3 K Answer-a (3)
(a) The average momentum of the molecules (b) The velocity of sound in the gas (c) The number of molecules in the gas (d) The mean square velocity of the molecules Answer-d (5)
(a) 800 K (b) 1600 K (c) 2400 K (d) 3200 K Answer-d (4)
(a) Proportional to √T (b) Proportional to T2 (c) Proportional to T3 (d) Zero Answer-a (13)
24×105 dyne/cm2 , the volume of O2 is 10 litre and mass is 20 gm. The m.s. velocity will be (a) 800 m/sec (b) 400 m/sec (c) 600 m/sec …
(a) – 123°C (b) 123°C (c) – 100°C (d) 0°C Answer-a (4)
(a) m (b) m/2 (c) m/4 (d) m/8 Answer-c (12)
(a) P1/(T1d1)=P2/(T2d2) (b) (P1T1)/d1=(P2T2)/d2 (c) (P1d2)/T1=(P2d1)/T2 (d) (P1d1)/T1=(P2d2)/T2 Answer-a (5)
(a) Increase in pressure (b) Increases in volume (c) Both (a) and (b) (d) None of these Answer-a (8)
(a) 2 J mol–1K–1 (b) 8.3 cal mol–1K–1 (c) 4.2 J mol–1K–1 (d) 2 cal mol–1K–1 Answer-d (17)
(a) 28g (b) 14×22.4 g (c) 56 g (d) None of these Answer-a (13)
300K and volume 1m3. If temperature and volume become double, then pressure will be (a) 105 N/m2 (b) 2×105 N/m2 (c) 0.5×105 N/m2 …
(a) 600°C (b) 177°C (c) 817°C (d) None of these Answer-b (8)
(a) 546°C (b) 182°C (c) 819°C (d) 646°C Answer-a (9)
O2 gas is taken at 27°C and pressure 76 cm. Of Hg. Then find out volume of gas (in litre) (a) 1.53 (b) …
[P+(a/V2)][v-b]=RT (a) Both a and b represent correction in volume (b) Both a and b represent adhesive force between molecules (c) a represents adhesive force between molecules and b correction in volume (d) a represents correction in volume and …
(a) The temperature must be 0 K (b) The temperature must be less than 0°C (c) The temperature must be less than the critical temperature (d) The temperature must be less than the reduced temperature Answer-c (5)
( T1,T2) volume (V1,V2) and pressure (P1,P2) respectively. If the valve joining the two vessels is opened, the temperature inside the vessel at equilibrium will be (a) T1 +T2 …
5°C , there occurred an increase of 1% in its pressure. The original temperature of the gas was (a) 500 °C (b) 273°C (c) 227°C …
27°C. Half of the mass of the gas is removed from the vessel and temperature of the remaining gas is increased to 87°C. Then the pressure of the gas in the vessel will be (a) 5 atm (b) 6 atm …
(a) Faster in solids than in liquids and gases (b) Faster in liquids than in solids and gases (c) Equal to solids, liquids and gases (d) Faster in gases than in liquids and solids Answer-d (18)
O2 gas (molar mass 32) at a temperature T. The pressure of the gas is P. An identical vessel containing one mole of He gas (molar mass 4) at temperature 2T has a pressure of (a) P/8 …
(a) It obeys Boyle’s law (b) It follows PV = RT (c) Internal energy depends on temperature only (d) It follows Vander-Waal’s equation Answer-d (12)
(a) Varies inversely as its mass (b) Varies inversely as the square of its mass (c) Varies linearly as its mass (d) Is independent of its mass Answer-c (8)
m1,m2 and m3 and the number of molecules in their respective containers are N1,N2 and N3 . The gas pressure in the containers are P1,P2 and P3 respectively. All the gases are now mixed and put in one of the …
(a) 2 (b) 4 (c) 1/4 (d) 1/2 Answer-d (6)
(a) 1092 K (b) 273 K (c) 546°C (d) 273°C Answer-d (2)
O2 is (a) PV = 8RT (b) PV = RT/4 (c) PV = RT (d) PV = RT/2 Answer-b (6)
(a) 1800°C (b) 162°C (c) 1527°C (d) 600°C Answer-c (87)
(a) Number of molecules (b) Atomic number (c) Mass number (d) Number of moles Answer-d (4)
1500 m3 of helium at 27°C and 4 atmospheric pressure. The value of helium at -3°C temperature and 2 atmospheric pressure will be (a) 1500 m3 (b) 1700 m3 (c) 1900 m3 (d) 2700 m3 Answer-d (7)
(a) 2 times (b) 4 times (c) (1/4) times (d) (1/2) times Answer-c (12)
27°C temperature and 30 atmospheric pressure is allowed to expand to the atmospheric pressure. If the volume becomes 10 times its initial volume, then the final temperature becomes (a) 100°C (b) 173°C (c) 273°C (d) – 173°C Answer-d (7)