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100° C the vapour pressure of a solution of 6.5g of a solute in 100 g water is 732mm. If Kb  = 0.52; the boiling point of this solution will be a. 101 ° C b. 100 ° C c. 102 …

a. 1 g b. 3g c. 6 g d. 18 g Ans. b (38)

a. HI b. HBr c. HCl d. HF Ans. c (12)

κPa and 4.556 κPa respectively, the composition of the vapour wll be a. 0.635 methanol, 0.365 ethanol b. 0.365 methanol, 0.635 ethanol c. 0.574 methanol, 0.326 ehanol d.  0.173 methanol, 0.827 Ans. b (50)

100°  C is a. 759.00 Torr b. 7. 60 Torr c. 76.00 Torr d. 752.40 Torr Ans. d (16)

a. Relative lowering of vapour pressure is independent b. The vapour pressure is a colligative property c. Vapour pressure of a solution is lower than the vapour pressure of the solvent d. The relative lowering of vapour pressure is directly …

cm3  of acetone is added to 100 cm3  of water, the vapour pressure of water over the solution a. it will be equal to the vapour pressure of pure water b. It will be less than the vapour pressure of …

a. Solute molecules and solvent molecules b. Solute molecules and the total molecules in the solution c. Solvent molecules and the total molecules in the solution d. Solvent molecules and the total number of ions of the solute Ans. b …

a. Equal to that of water b. Equal to that of methanol c. More than that of water d. Less than that of water Ans. c Explanation : Methanol has low boiling point than H2 O lower is boiling point …

2985 N / m2 . The vapour pressure of pure water is 3000 N/ m2 . The molecular weight of the solute is a. 60 b. 120 c. 180 d. 380 Ans. c (13)

25 ° C .(Given : Vapour pressure Date at 25 ° C   benzene = 12.8 κPa, Toluene = 3.85 κPa ) a. The vapour will contain a higher percentage of benzene b. The vapour will contain a higher percentage of toluene …

2  ° C . Assuming concentration of solute is much lower than the concentration of solution is a. 724 b. 740 c. 736 d. 718 Ans. a (37)

a. Concentration of solution containing non-volatile solute b. Temperature upto boiling point c. Temperature upto triple point d. Altitude of the concerned place of boiling Ans : b (13)

PA o  : PB o  = 1 : 2  and have mole fraction in solution 1: 2 then mole fraction of A in vapours a. 0.33 b. 0.25 c. 0.52 d. 0.2 Ans. d (12)

80° C the vapour pressure of pure liquid ‘A’ is 520 mmHg and that of pure liquid ‘B’ is 1000 mmHg. If a mixture of solution ‘A’ and ‘B’ boils at 80° C and 1 atm pressure the amount of …

25 C is 23. 8 mm Hg a. 1.25 mm Hg b. 0.125 mm Hg c. 1.15 mm Hg d. 00.12 mm Hg Ans. b (12)

20° C are 440 mmHg for pentane and 120 mmHg for hexane. The mole fraction of pentane in the vapour phase would be a. 0.549 b. 0.200 c. 0.786 d. 0.478 Ans. d (13)

a. 1 M C12 H22 O11 b. 1 M CH3 COOH c. 1 M CaCl 2 d. 1 M NaCl Ans. a (13)

At a given temperature, which of the following statement is correct about the vapour pressure of pure water and that of NaCl solution a. Vapour pressure in container (A)  is more than that in container (B) b. Vapour pressure in …

0.1 °C  higher than that of the pure ether. The molecular weight of the substance will be be a. 148 b. 158 c. 168 d. 178 Ans. b (10)

CH4  and H2  are mixed in an empty container at 25° C. The fraction of the total pressure exerted by  H2 is a. 1/9 b. 1/2 c. 8/9 d. 16/17 Ans. c (15)

a. Same as that of 2nd   solution b. Nearly one fifth of the  2nd solution c. Double that of 2nd  solution d. Nearly five times that of 2nd solution Ans. a (15)

a. Vapour pressure of solute is zero b. Vapour pressure of solvent is zero c. Vapour pressure of solution is more than vapour pressure of solvent d. all of the options Ans. a Explanation : Non volatile solute always have …

Po and P are the vapour pressure of the pure solvent and solution and n1  and n2 are the moles of solute and solvent  respectively in the solution then the correct relation between P and Po  is a. Po = …

20° C is 185 torr. When 1.2 g of a non volatile substance was dissolved in 100 g of acetone at 20° C its vapour pressure was 183 torr. The molar mass of the substance is a. 32 b. 64 …