2.57 x 10 -3 bar. The molar mass of protein will be a. 31011 g mol -1 b. 61038 g mol -1 c. 51022 g mol -1 d. 122044 g mol -1 Ans. b (9)
dm-3 sucrose solution at 20 ° C (molar gas constant, R = 8.314 JK -1 mol -1 ; 1 dm-3 = 0.001 m3 ) a. 4870 Pa b. 4.87 Pa c. 0.00487 Pa d. 0.33 Pa Ans. a (17)
BaCl2 solutions are separated by a semi permeable membrane in a container. For this system choose the correct answer. a. There is no movement of any solution across the membrane b. Water flows from BaCl2 solution towards NaCl solution c. …
a. 0.16 M NaCl b. Conc. NaCl c. 50% NaCl d. 30% NaCl Ans. a Explanation : 9g of NaCl is added in water to make 1L solution which is isotonic with blood. (8)
a. Units of atmospheric pressure and osmotic pressure are the same b. In reverse osmosis, solvent molecules move through a semipermeable membrane from a region of lower concentration of solute to a regain of higher concentration c. The value of …
a. Elevation in boiling point b. Viscosity c. Osmosis d. Dialysis Ans. d (8)
MgCl2 and solution B contains 7 g/L of NaCl. At room temperature, the osmotic pressure of a. Solutions A is greater than B b. Both have same osmotic pressure c. Solute B is greater than A d. Can’t determine Ans.c …
a. All solutions b. Solutions of non-electrolytes only c. Solutions of electrolytes only d. None of these Ans. b Explanation : Equal osmotic pressure only applicable of non electrolytes solution at low concentration (16)
a. They will have the same osmotic pressure b. They have the same weight concentrations c. Osmosis does not take place when the two solutions are separated by a semipermeable membrane d. They will have the same vapour pressure Ans. …
a. Berkeley and Hartley’s method b. Morse’s method c. Pfeffer’s method d. De Vries method Ans. a (11)
a. Calcium sulphate b. Barium oxalate c. Nickel phosphate d. Copper ferrocyanide Ans.d Explanation : Copper ferrocyanide ppt. acts as a semipermeable membrane (17)
a. 1. 64 atm b. 2.46 atm c. 2.06 atm d. 0.82 atm Ans. c (12)
a. It gains water due to osmosis b. It loses water due to reverse osmosis c. It gains water due to reverse osmosis d. It loses water due to osmosis Ans. d Explanation : When an unripe mango is placed …
CH2 O . A solution containing 6g of the compound exerts the same osmotic pressure as that of 0.05 M glucose solution at the same temperature. The molecular formula of the compound is a. C2 H4 O2 b. C3 H6 …
dm3 of urea (molecular mass = 60 gmol-1 ) is isotonic with a 5% solution of a non volatile solute. The molecular mass of this non volatile solute is a. 300 g mol -1 b. 350 g mol -1 c. 200 g mol -1 d. …
a. increasing the temperature of the solution b. Decreasing the temperature of the solution c. Increasing the volume of the vessel d. Diluting the solution Ans. a (10)
a. Osmosis b. Reverse osmosis c. Filtration d. Diffusion Ans. b (10)
a. The solute must be volatile b. The solution concentration must be high c. The solute should undergo dissociation d. The solute must be non – volatile Ans. d Explanation : To get precise values of molar mass of a …
150 ° C is a. 2.45 atm b. 5.078 atm c. 3.4 atm d. 4 atm Ans. b (33)
a. Benzene – toluene b. Water – ethyl alcohol c. Water – nitric acid d. Water – hydrochloric acid Ans. a Explanation : Aromatic compound generally separated by fractional distillation. e.g. Benzene + Toluene. (43)
a. HNO3 + H2 O solution b. C2 H5 OH + H2 O solution c. C6 H6 + C6 H5 CH3 solution d. None of these Ans. a (12)
a. Binary liquid mixture b. Axzeotropic mixture c. Eutectic mixture d. Ideal mixture Ans. b (6)
a. Shows a negative deviation from Raoult’s law b. Shows no deviation from Raoult’s law c. Shows positive deviation from Raoult’s law d. Is saturated Ans. c Explanation : When the solution shows deviation from Raoult’s there is an itnermediate …
103 Pa and 12 x 103 Pa, respectively. The containing 40 mole percent of A at this temperature is : a. xA = 0.28; xB = 0.72 b. xA = 0.76; xB = 0.24 c. xA = 0.37; xB = …
i. Pure solvent → separated solvent molecules ΔH1 ii. Pure solvent → separated solvent molecules ΔH2 iii. Separated solvent and solute molecules → solution ΔH3 Solution so formed will be ideal if a. ΔHsoln = ΔH3 – ΔH1 – ΔH2 b. ΔHsoln …
a. ΔG mix = 0 b. ΔH mix = 0 c. ΔU mix = 0 d. ΔP = P obs – P calculated by Raoult’s law = 0 Answer. a (14)
6.0 x 10 -4 atmosphere at 300K, the value of R used is 0.082 litre atmosphere K . The molecular -1 K -1 mass of polymer was found to be a. 3.0 x 102 b. 1.6 x 10 5 c. 5.6 x 104 d. …
10 ° C is 500 mm. Osmotic pressure of the solution become 105.3 mm. when it is dilute and temperauter raised to 25° C . the extent of dilution is a. 6 times b. 5 time c. 7 time d. …
KNO3 and CH3 COOH are prepared separately. Molarity of both is 0.1 M and osmotic pressures are P1 and P2 respectively. The correct relationship between the osmotic pressure is a. P2 > P1 b. P1 = P 2 c. P1 > …
dm3 of urea is isotonic with a 5 % solution of a nonvolatile solute. The molecular mass of this nonvolatile solute is a. 350 g mol-1 b. 200 g mol-1 c. 250 g mol-1 d. 300 g mol-1 Ans. d …
a. 200 mL of 2 M NaCl solution b. 200 mL of 1 M glucose solution c. 200 mL of 2 M urea solution d. all have osmotic pressure Ans. b (13)
a. 136. 2 b. 68.4 c. 34.2 d. 171. 2 Ans. b (5)
a. 0.1M gulcose b. o.1 M KCl c. 0.6% glucose solution d. 0.6 % KCl solution Ans. a Explanation : Isotonic solutions are those which have same concentration (13)
a. Equal temperature b. Equal osmotic pressure c. Equal volume d. Equal amount of solute Ans. b (5)
a. Sugar beet will lose water from its cells b. Sugar beet will absorb water from solution c. Sugar beet will neither absorb nor lose water d. Sugar beet will dissolve in solution Ans. a Explanation : Flow of liquid …
gcm-3 , molar mass of the substance will be a. 90.0 g mol -1 b. 115.0 g mol -1 c. 105.0 gmol -1 d. 210.0 gmol -1 Ans. d (8)
a. Isotonic b. Isomotic c. Hypertonic d. Equinormal Ans. a Explanation : Isotonic mixtures have equal osmotic pressure so there won’t be any flow of liquid between the blood cells and blood. (7)
15° C , then molecular weight of the solute is a. 1000 b. 1200 c. 1400 d. 1800 Ans. b (5)
37 ° C . What is the concentration of an aqueous NaCl a. 0.16 mol/L b. 0.32 mol / L c. 0.60 mol/ L d. 0. 45 mol/ L Ans. b (26)
a. Relative lowering of vapour pressure b. Elevation of boiling point c. Depression in freezing point d. Osmotic pressure e. Rast’s method Ans. d Explanation : Osmotic pressure method is especially suitable for the determination of molecular masses of macro …