Flame Institute SCF 18 Near Chawla Lights Phase 7 Mohali Chandigarh 9888949978

0

Shopping cart

Close

No products in the cart.

Flame SCF 18 Near Chawla Lights Ph-7 Mohali 9888949978

A particle of mass m is moving in a horizontal circle of radius r under a centripetal force equal to -K/r2 , where K is a constant. The total energy of the particle is

a) K/2r (b) – (K/2r)

(c) -(K/r) (d) K/r

Answer: b

5/5 - (1 vote)

PrevPreviousThe displacement x of a particle moving in one dimension under the action of a constant force is related to the time t by the equation t=√x+3 , where x is in meters and t is in seconds. The work done by the force in the first 6 seconds is

NextIf W1, W2 ,and W3 represent the work done in moving a particle from A to B along three different paths 1, 2 and 3 respectively (as shown) in the gravitational field of a point mass m, find the correct relation between W1, W2 and WNext

You May Also Like

Sign up to receive latest updates

Get in touch

Need some help?

Create Account

Popular subjects

Need some help?

© 2026 Flame Institute.All rights reserved.

Call Now Button