Two particles of equal mass go round a circle of radius R under the action of their mutual gravitational attraction. The speed of each particle is
(a) v = 1/2R √1/gm (b) v =√gm /2R
(c) v=1/2√gm/R (d) v=√4gm/R
Answer: c
(9)
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(a) – 5 J (b) – 10 J (c) – 15 J (d) – 20 J Answer-a (126)