3. An inverted bell lying at the bottom of a lake 47.6 m deep has

50 cm³ of air trapped in it. The bell is brought to the surface of the lake. The volume of the trapped air will be (atmospheric pressure = 70 cm of Hg and density of Hg = 13.6 g/cm³)An inverted bell lying at the bottom of a lake 47.6 m deep has 50 cm³ of air trapped in it. The bell is brought to the surface of the lake. The volume of the trapped air will be (atmospheric pressure = 70 cm of Hg and density of Hg = 13.6 g/cm³)

(a)  350 cm³                                          (b)   300 cm³

(c)   250 cm³                                         (d)   22 cm³

Answer- b

(12)