23. The elastic energy stored in a wire of Young’s modulus Y is
(a) Y×(Strain2/Volume)
(b) Stress × Strain × Volume
(c) (Stress2×Volume) / (2Y)
(d) (1/Y) × Stress × Strain × Volume
Answer-c
(12)
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(a) – 5 J (b) – 10 J (c) – 15 J (d) – 20 J Answer-a (123)