a. o.97 N b. 0.142 N c. 0.194 N d. 0.244 N Ans. c (12)
N H2 SO4 and the mixture is made one litre. Normality of the mixture will be a. 0.56 N b. 0.50 N c. 0.40 N d. 0.35 N Ans. b (6)
H2 SO4 (18 molar) is diluted to 1 litre. The approximate strength of dilute acid could be a. 0.18 N b. 0.09 N c. 0.36 N d. 1800 N Ans. c (12)
a. 13. 25 g b. 26. 5 g c. 53 g d. 6.125 g Ans. a (10)
a. HCl b. perchloric acid c. HNO3 d. phosphoric acid Ans. d (10)
a. 40 mL b. 20mL c. 10mL d. 60 mL Ans. a (8)
a. 2N b.4N c. N/2 d. N/4 Ans. b Explanation : N = M x basicity ; N = 2 x 2 = 4 (14)
a. 0. 5 L of A + 1.5 L of B b. 1.5 L of A + 0.5 L of B c. 1.0 L of A + 1.0 L of B d. 0. 75 L of A + 1.25 L …
1.2046 x 106 hydrochloric acid molecules in one dm3 of the solution . The strength of the solution is a. 6 N b. 2N c. 4N d. 8 N Ans. b (13)
10N HNO3 to get 0.1 N HNO3 a. 1000 mL b. 990 mL c. 1010 mL d. 10 mL Ans. b Explanation : N1 V1 = N2 V2 10 x 10 = 0.1 (10+V) V = 10 x 10 / …
100 cm3 of 0.5 N H2 SO4 to get decinormal concentration is a. 400 cm3 b. 500cm3 c. 450 cm3 d. 100 cm3 Ans.a (7)
a. 1g b. 2g c. 10 g d. 20 g Ans. a (3)
(a) Becomes concave toward A (b) Becomes convex towards A (c) Remains in the initial position (d) Either (a) or (b) depending on the size of A w.r.t. B Ans. a (15)
(a) MLT-1 (b) ML2 T-2 (c) ML0 T-2 (d) ML-1T-2 Ans. c (9)
(a) Specific weight of liquid lead (b) Specific gravity of liquid lead (c) Compressibility of liquid lead (d) Surface tension of liquid lead Ans. d (6)
(a) Magnetic substances (b) Molecules of different substances (c) Molecules of same substances (d) None of these Ans. (c) The cohesive force is the force of attraction between the molecules of same substance (15)
(a) Surface tension of water is very high (b) Surface tension of water is very low (c) Viscosity of oil is high (d) Viscosity of water is high Ans. a (58)
a. 100 L b. 10 L c. 1L d. 1000 L Ans. b (8)
The force required to separate two glass plates of area 10-2m2 with a film of water 0.05 mm thick between them, is (Surface tension of water is 70 x 10-3 N/m) (a) 28 N (b) 14 N (c) 50 N …
(a) Viscosity (b) Surface tension (c) Weight (d) Floating force Ans. b (12)
a. 8 g of KOH / L b. N phosphoric acid c. 6 g of NaOH/ 100 mL d. 0.5 M H2 SO4 Ans. c (13)
(a) Surface tension is more (b) Surface tension is less (c) Consumes less soap (d) None of these Ans. (b) Surface tension of water decrease with rise in temperature. (9)
a. 0.1 b. 40 c. 1.0 d. 0.4 Ans. c (11)
A 10 cm long wire is placed horizontally on the surface of water and is gently pulled up with a force of 2 ×10-2 N to keep the wire in equilibrium. The surface tension, in Nm-1, of water is (a) …
K2 Cr2 O7 required to prepare 100 mL of its 0.05 N solution is a. 2. 9424 g b. 0.4904 g c. 1.4712 g d. 0.2452 g Ans. d (8)
a. 0.75 litre of 10 N HCl and 0.25 litre of 4 N HCl b. 0.25 litre of 4 N HCl and 0.75 litre of 10 N HCl c. 0.67 litre of 4 N HCl and 0.33 litre of 10 …
(a) 2πrT + W (b) 2πrT COSθ – W (c) 2πrT COSθ +W (d) W-2πrT COSθ Ans. c (11)
a. 1.5 M b. 1.66 M c. 0.017 M d. 1.59 M Ans. b (8)
H2 O2 solution of ’10 volume’ is a. 30% b. 3% c. 1% d. 10% Ans. b (5)
(a) Atmospheric pressure exerts a force on a liquid drop (b) Volume of a spherical drop is minimum (c) Gravitational force acts upon the drop (d) Liquid tends to have the minimum surface area due to surface tension Ans. (d) …
FeCl3 (formula mass = 162 ) has a density of 1.1 g/mL and contains 20.o% FeCl3 . Molar concentration of this solution is a. 0.028 b. 0.135 1.27 d. 1. 47 Ans. b (13)
a. x= y b. x = 2y c. x = 2y d. None of the above Ans. b (20)
(a) Inertia (b) Pressure (c) Surface tension (d) Viscosity Ans. (c) Surface tension pulls the plates towards each other. (6)
a. 0.01 M b. 0.10 M c. 0.001 M d. 0.0001 M Ans. b Explanation : Molarity is intrinsic property. Hence it is independent of amount of solution (17)
HNO3 should be used to prepare 250mL of 2.0 M HNO3 a. 53. 0 g conc. HNO3 b. 45.0 g conc. HNO3 c.90.0 g conc. HNO3 d. 70.0 g conc. HNO3 Ans. b (12)
AgNO3 which of the following will be formula of the chloride (X stands for the symbol of the element other than chlorine) a. X2 Cl2 b. XCl2 c. XCl4 d. X 2Cl Ans. b (4)
H2 SO4 (Molar mass = 98 g mol -1 ) by mass will be a. 1.64 b. 1.88 c. 1.22 d. 1.45 Ans. c (81)
0.9 g L-1 , what will be the molarity of glucose in blood a. 5 M b. 50 M c. 0.005 M d. 0.5 M Ans. c (8)
a. 55.6 b. 5.56 c. 100 d. 20.08 Ans. a Explanation : molarity of pure water = 1000/18 = 55.6 M (6)