(a) x=√D(H-D) (b) x=√[D(H-D)]/2 (c) x=2√D(H-D) (d) x=4√D(H-D) Answer-c (3)
(a) The water in the tube rises to height v2 /2g (b) The water in the tube rises to height g/2v2 (c) The water in the tube does not rise at all (d) None of these Answer-a (71)
(a) Zero (b) 20.0 cm (c) 10.6 cm (d) 40.0 cm Answer-b (9)
660 kgm–3. The velocity with which gasoline begins to shoot out of the hole is (a) 27.8 m/s (b) 41.0 m/s (c) 9.6 m/s (d) 19.7 m/s Answer-b …
A1 and A2 , are v1 and v2 The difference in the levels of the liquid in the two vertical tubes is h (a) The volume of the liquid flowing through the tube in unit time is A1v1 (b) v2 …
vA and vB , and pressure PA and PB at points A and B respectively (a) vA = vB (b) vB > vA (c) PA = PB (d) PB > PA Answer- a,d (164)
(a) 282.8 cm/sec (b) 432.6 cm/sec (c) 632.6 cm/sec (d) 832.6 cm/sec Answer-a (9)
(a) Upthrust of the air which will be equal to the weight of the air having the same volume as the plane (b) Force due to the pressure difference between the upper and lower surfaces of the wings, created by …
[P/(ρg)]+ h + (1/2)(v2/g) The terms A, B and C are generally called respectively: (a) Gravitational head, pressure head and velocity head (b) Gravity, gravitational head and velocity head (c) Pressure head, gravitational head and velocity head (d) Gravity, pressure …
(a) Move up (b) Move down (c) Move erratically (d) Remain at the same level Answer-b (18)
(a) Bernoulli’s theorem (b) Boyle’s law (c) Archimedes principle (d) Newton’s law of motion Answer-a (9)
(a) Dynamic lift of an aeroplane (b) Viscosity meter (c) Capillary rise (d) Hydraulic press Answer-a (11)
(a) The speed of a particle always remains same (b) The velocity of a particle always remains same (c) The kinetic energies of all the particles arriving at a given point are the same (d) The moments of all the …
a. Elevation in boiling point b. Viscosity c. Osmosis d. Dialysis Ans. d (8)
A1 and A2 are the cross-sections of the portions of the tube as shown. Then the ratio of speeds v1 / v2 will be (a) A1 / A2 (b) A2/ A1 (c) √A2 / …
MgCl2 and solution B contains 7 g/L of NaCl. At room temperature, the osmotic pressure of a. Solutions A is greater than B b. Both have same osmotic pressure c. Solute B is greater than A d. Can’t determine Ans.c …
a. All solutions b. Solutions of non-electrolytes only c. Solutions of electrolytes only d. None of these Ans. b Explanation : Equal osmotic pressure only applicable of non electrolytes solution at low concentration (16)
a. They will have the same osmotic pressure b. They have the same weight concentrations c. Osmosis does not take place when the two solutions are separated by a semipermeable membrane d. They will have the same vapour pressure Ans. …
a. Berkeley and Hartley’s method b. Morse’s method c. Pfeffer’s method d. De Vries method Ans. a (11)
a. Calcium sulphate b. Barium oxalate c. Nickel phosphate d. Copper ferrocyanide Ans.d Explanation : Copper ferrocyanide ppt. acts as a semipermeable membrane (17)
(a) Maximum speed and least pressure (b) Maximum pressure and least speed (c) Both pressure and speed maximum (d) Both pressure and speed least Answer-a (4)
(a) 4 : 9 (b) 9 : 4 (c) 8 : 27 (d) 1 : 1 Answer-a (12)
a. 1. 64 atm b. 2.46 atm c. 2.06 atm d. 0.82 atm Ans. c (12)
(a) Gravity to viscous force (b) Gravity force to pressure force (c) Inertia forces to viscous force (d) Viscous forces to pressure forces Answer-c (19)
(a) Zero (b) Maximum (c) In between zero and maximum (d) Equal to critical velocity Answer-a (4)
a. It gains water due to osmosis b. It loses water due to reverse osmosis c. It gains water due to reverse osmosis d. It loses water due to osmosis Ans. d Explanation : When an unripe mango is placed …
T1 and T2. Their lengths are l1 and l2 and radii of cross-section are r1 and r2 The rate of flow of water under a pressure difference P through tube T1 is 8cm3/sec. If l1 = 2l2 and r1 =r2, …
CH2 O . A solution containing 6g of the compound exerts the same osmotic pressure as that of 0.05 M glucose solution at the same temperature. The molecular formula of the compound is a. C2 H4 O2 b. C3 H6 …
dm3 of urea (molecular mass = 60 gmol-1 ) is isotonic with a 5% solution of a non volatile solute. The molecular mass of this non volatile solute is a. 300 g mol -1 b. 350 g mol -1 c. 200 g mol -1 d. …
a. increasing the temperature of the solution b. Decreasing the temperature of the solution c. Increasing the volume of the vessel d. Diluting the solution Ans. a (10)
a. Osmosis b. Reverse osmosis c. Filtration d. Diffusion Ans. b (10)
a. The solute must be volatile b. The solution concentration must be high c. The solute should undergo dissociation d. The solute must be non – volatile Ans. d Explanation : To get precise values of molar mass of a …
150 ° C is a. 2.45 atm b. 5.078 atm c. 3.4 atm d. 4 atm Ans. b (33)
radius is (Surface tension of the soap solution is (3/100) N/m) (a) 75.36 x 10-4 joule (b) 37.68 x 10-4 joule (c) 150.72 x 10-4 joule (d) 75.36 joule Ans. a (10)
a. Benzene – toluene b. Water – ethyl alcohol c. Water – nitric acid d. Water – hydrochloric acid Ans. a Explanation : Aromatic compound generally separated by fractional distillation. e.g. Benzene + Toluene. (43)
size 10 cm x 10 cm is (Surface tension T= 3 x 10-2 Nm (a)6 x 10-4 j (b) 3 x 10-4 j (c) 6 x 10-3 j d) 3 x 10-4 j Ans. a (10)
a. HNO3 + H2 O solution b. C2 H5 OH + H2 O solution c. C6 H6 + C6 H5 CH3 solution d. None of these Ans. a (12)
a. Binary liquid mixture b. Axzeotropic mixture c. Eutectic mixture d. Ideal mixture Ans. b (6)
a. Shows a negative deviation from Raoult’s law b. Shows no deviation from Raoult’s law c. Shows positive deviation from Raoult’s law d. Is saturated Ans. c Explanation : When the solution shows deviation from Raoult’s there is an itnermediate …