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PUBLIC NOTICE 25 August 2024 Sub: Information Regarding Challenge of Provisional Answer Key, Display of Scanned Images of OMR Answer Sheet and Display of Recorded Response for National Eligibility cum Entrance Test (UG) – 2024 – Reg. National Testing Agency …
(a) (2/5)R (b) (5/2)R (c) (10/3)R (d) (6/7)R Ans. c (9)
temperature is T0, atmospheric pressure is also P0. Now the temperature of the gas is increased to 2T0, the tension in the wire will be (a) 2P0A …
volume V1 to V2 for a gas which obeys Vander Waal’s equation (V – βn)[ P + (αn2/v)= nRT (a) nRT loge( V2 – nβ/V1– nβ) + α n2(V1 -V2)/V1V2 (b) nRT log10 ( V2 – αβ/V1– αβ) + α n2(V1 -V2)/V1V2 …
(a) P3 > P1 , W > 0 (b) P3 < P1 , W < 0 (c) P3 > P1 , W < 0 (d) P3 = P1 , W = 0 Ans. …
(a) 4 RT (b) 15 RT (c) 9 RT (d) 11 RT Ans. d (6)
(a) PV3/2 = constant (b) PV5/2 = constant (c) PV7/3 = constant (d) PV4/3= constant Answer-a (7)
(a) 5% (b) 6% (c) 7% (d) 8% Answer-c (4)
(a) (2/5)R (b) (5/2)R (c) (10/3)R (d) …
P0 and temperature is T0, atmospheric pressure is also P0. Now the temperature of the gas is increased to 2T0, the tension in the wire will be (a) 2P0 A …
V1 to V2 for a gas which obeys Vander Waal’s equation (V-βn)[P+(αn2/V)]=nRT (a) nRT loge [ (V2-nβ)/( V1-nβ) ]+αn2[(V1 – V2)/(V1 V2)] (b) nRT log10 [ (V2-nβ)/( V1-nβ) ]+αn2[(V1 – V2)/(V1 V2)] (c) nRT loge [ (V2-nα)/( V1-nα) ]+βn2[(V1 – V2)/(V1 V2)] (d) …
V1 to V2 and then compressed to original volume V1 adiabatically. Initial pressure is P1 and final pressure is P3 . The total work done is W. Then (a) P3 > P1 ,W > 0 …
(a) 4 RT (b) 15 RT (c) 9 RT (d) 11 RT Answer-d (3)
(a) (2/3)Q (b) (3/5)Q (c) (2/5) Q (d)(1/5)Q Ans. c (9)
at 00C and also contains an insulated piston of negligible weight and negligible thickness at the middle point. The gas on one side of the piston is heated to 1000c. If the piston moves 5cm the length of the hollow …
T1, is enclosed in a cylinder fitted with a frictionless piston. The gas is allowed to expand adiabatically to a temperature. T2 by releasing the piston suddenly. If L1 and L2 are the lengths of the gas column before and …
The mass of the gas in A is mB and that in B is . The gas in each cylinder is now allowed to expand isothermally to the same final volume 2V. The changes in the pressure in A and …
(a) Transfer of heat by radiation (b) Electrical heating of a nichrome wire (c) Transfer of heat by conduction (d) Isothermal compression Ans. d (16)
(a) Positive work is done by ice-water system on the atmosphere (b) Positive work is done on the ice-water system by the atmosphere (c) The internal energy of the ice-water system increases (d) The internal energy of the ice-water system …
volume of 1671 cm3 .If the atmospheric pressure = 1.013 x 105 N/m3 and the mechanical equivalent of heat = 4.19 J/calorie , the energy spent in this process in overcoming intermolecular forces is (a) 540 cal (b) 40 cal …
between 227°C and 127°C. It absorbs 6 x 104 cals of heat at higher temperature. Amount of heat converted to work is (a) 2.4 x 104 cal (b) 6 x 104 cal (c) 6 x …
at temperature 727°C and 227°C. The maximum possible efficiency of such an engine is (a) 1/2 (b) 1/4 (c) 3/4 (d) 1 Ans. a (13)
of – 23°C and the compressed gas in the condenser has a temperature of 27°C. The theoretical coefficient of performance is (a) 5 (b) 8 (c) 6 (d) 6.5 Ans. a (21)
-130c . The coefficient of performance of the engine is 5. The temperature of the air (to which heat is rejected) will be (a) 325°C (b) 325K (c) 39°C (d) 320°C Ans. c (15)
Lorem Ipsum is simply dummy text of the printing and typesetting industry. Lorem Ipsum has been the industry’s standard dummy text ever since the 1500s, when an unknown printer took a galley of type and scrambled it to make a …
Lorem Ipsum is simply dummy text of the printing and typesetting industry. Lorem Ipsum has been the industry’s standard dummy text ever since the 1500s, when an unknown printer took a galley of type and scrambled it to make a …