12. The radii of two soap bubbles
are r1 and r2. In isothermal conditions, two meet together in vaccum. Then the radius of the resultant bubble is given by
(a) R= (r1+r2)/2
(b) R= r1 (r1 r2+r2)
(c) R2 = r21+r22
(d) R= r1+r2
Ans. c
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(a) – 5 J (b) – 10 J (c) – 15 J (d) – 20 J Answer-a